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Old 06-21-2018, 05:13 PM   #73
HumbleBeauty
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denying these three axioms

ΔE/Δt = ΔP
Δs/Δt = Δv
ΔE/Δs = ∇E

we would be left with

ΔE/Δt = ΔE/Δs (Δs/Δt)

dE/Δt = ΔE/Δs (ds/Δt)

∫dE/Δt = ∫ΔE/Δs (ds/Δt)

E/Δt = ΔE/Δs (s/Δt)

E = ΔE/Δs (s)

E = ΔE (s/Δs)

E/ΔE = s/Δs

E/s = ΔE/Δs

E ds = s dE

∫E ds = ∫s dE


Quote:
Davin wrote View Post
The change in energy divided by the change in time, equals the change in power. This doesn't make sense.
E/t = P

Quote:
The change in speed divided by the change in time equals the change in velocity. This is not right, it should just equal velocity not the delta of velocity.
s stands for space x

Δx/Δt = Δv

Quote:
The change in energy divided by the change in speed equals the derivative of energy. Why is energy being divided by speed and how does that make the derivative of energy? This doesn't make sense.
ΔE/Δx = ∇E, nabla is the gradient

Quote:
The change in energy divided by the change in time equals the change in energy divided by the change in time. Do you realize that you put the same thing on both sides of the equation? x = x, well of course it does, but what's your point?
just showing my work

Quote:
The change in velocity just sitting out there doesn't make any sense.
I mean times * like E = m c^2

everyone knows you multiply
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